Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A

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Prove that : `tantheta+tantheta+tan(90^(@)-theta)=sectheta*sec(90

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Solved QUESTION 1 T Construct an appropriate triangle to

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i) (1 + tan A)/ sin A + (1 + cot A)/ cos A = 2 (sec A + cosec A

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SOLVED: Sec (90 -A) sinA = cot (90-A). tan( 90- A)

If sec 5θ = csc (θ - 36°), where 5θ is an acute angle, then find

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Prove the following: (cos(90^0-theta)sec(90^0-theta)t a ntheta)/(cosec

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Prove that: tan (90° - A) cot A/ cosec^2 A - cos^2 A = 0